U=10V R=2 omy t=1s. Ile wynosi I,P,Q,W
dane:
U = 10 V
R = 2 Ω
t = 1 s
szukane:
P, Q, W
Moc prądu elektrycznego:
P = U·I
z prawa Ohma:
R = U/I I*I
R·I = U /:R
I = U/R = 10V/2Ω = 5 A
I = 5 A
---------
P = 10V·5A
P = 50 W
=======
Wielkość ładunku:
I = Q/t I*t
Q = I·t = 5A·1s
Q = 5 C
======
Praca prądu elektrycznego:
W = U·I·t
W = 10V·5A·1s
W = 50 W
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dane:
U = 10 V
R = 2 Ω
t = 1 s
szukane:
P, Q, W
Moc prądu elektrycznego:
P = U·I
z prawa Ohma:
R = U/I I*I
R·I = U /:R
I = U/R = 10V/2Ω = 5 A
I = 5 A
---------
P = 10V·5A
P = 50 W
=======
Wielkość ładunku:
I = Q/t I*t
Q = I·t = 5A·1s
Q = 5 C
======
Praca prądu elektrycznego:
W = U·I·t
W = 10V·5A·1s
W = 50 W
=======