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Verified answer
Jawabf(x) = (x + 5) √(3 - 2x)
u = x + 5
u' = 1
v = √(3-2x)
v' = 1/2 (-2)/ √(3-2x)
v' = - 1/ √(3-2x)
f'x = u'v + uv'
= 1.√(3 -2x) - (x+5)/ √(3- 2x)
=(3 - 2x - x - 5) / √(3 -2x)
= (- 3x - 2) / √(3 - 2x)
= (-3x - 2)(√(3 -2x) / (3 -2x)