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f'x = (u'v -u v ') /(v²)
u=x³ - 3 x² +2x+1 dan u' = 3 x² - 6x +2
v=x²+1 dan v'=2x
f'x=((3 x² - 6x +2)(x²+1) - (x³ - 3 x² +2x+1)(2x))/((x²+1)(x²+1))
= (3x^4 -6 x³ + 2x² +3 x² - 6x +2 - 2x^4 + 6 x³ - 4 x²+2x /()()
=(x^4 + x² - 4x +2)/(x²+1)(x²+1)