Turunan pertama dari f(x)=4x+ ½.... Question from @naa012155

August 2022 2 5 Report

Turunan pertama dari f(x)=4x+ ½

Fazm1

Rumus Turunan

ax^n = anx^n-1

f (x) = 4x + ½

f '(x) = 4.1x^1-1

= 4x^0

= 4

3 votes Thanks 2

naa012155 Makasih kak bantuanya

Fazm1 sama"

CallMeChan01

${ \sf{ax {}^{n} = anx {}^{n - 1} }}$

${ \sf{f(x) = 4x + \frac{1}{2} }}$

${ \sf{f(x) = 4x {}^{1 - 1} }}$

${ \sf{ \: \: \: \: \: \: \: \: = { \underline{ \boxed{ \red{4x {}^{0} }}}}}}$

${ \underline{ \boxed{ \red{4}}}}$

꒷ ͝ ꒦ ͝͝͝ ꒷ ͝ ꒦ ͝͝͝ ꒷ ͝ ꒦ ͝͝͝ ꒷ ͝ ꒦ ͝͝͝ ꒷ ͝ ꒦ ͝͝͝ ꒷ ͝ ꒦ ͝͝͝

$\purple{ \boxed{ \blue{ \boxed{ \pink{ \star \: { \purple{ \tt{JW} \: { \pink { \star}}}}}}}}}$

${ \sf { \cancel{cmiw}}}$

1 votes Thanks 1

" Life is not a problem to be solved but a reality to be experienced! "