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Verified answer
F(x) = (sin^2 3x)^1/3= (sin 3x)^2/3
f'(x) = (2/3) (sin 3x)^(-1/3) . cos 3x . 3
= 2 cos 3x / (sin 3x)^1/3
= 2 cos 3x / (sin 3x)^1/3 . (sin 3x)^2/3 / (sin 3x)^2/3
= 2 cos 3x . (sin 3x)^2/3 / (sin 3x)
= 2 (cos 3x)/(sin 3x) . (sin 3x)^2/3
= 2 cot 3x . (sin 3x)^2/3
^ = pangkat