Question

Turunan pertama dari fungsi f(x)=(2x-7)pangkat5 (dikali) (3x+1)

Answer 1

f(x) = (2x-7)pangkat5 (dikali) (3x+1) 
f(x)' = 5(2x-7)pangkat4 (dikali) (3)
f(x)' = 5(dikali)3 (2x-7)pangkat4
f(x)' = 15 (2x-7)pangkat4

Answer 2

F(x) = (2x-7)^5
f'(X) = 5(2x-7) . 2
=10(2x-7)

g(x) = (3x+1)
g'(x) = 3

h(x) = f(x) g'(x) + f'(x) g(x)
= (2x-5)^7 (3) + 10(2x-7) (3x+1)