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12 16 20 24 selisih tengah
4 4 4 selisih bawah
rumus fungsi = an^2+bn+c
2a = selisih bawah
2a = 4
a = 2
3a+b= seisih tengah
3(2) + b = 12
6 + b = 12
b = 6
a+b+c = selisih atas
2+6+c=8
c=0
f(n) = 2n^2 + 6n