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dijawab : y-y₁=y₂-y₁
x-x₁ x₂-x₁
y-6= (-6)-6
x-2 (-1)-2
y-6= -12 ⇒dikali silang
x-2 -3
-3(y-6)= -12(x-2)
-3y-18= -12×+24
-3y=-12×+24+18
-3y= -12×+42
b) melalui 2 titik (1,3) dan (8,-5)
y-y₁=y₂-y₁
x-x₁ x₂-x₁
y-3= (-5)-3
×-1 8-1
y-3= -8⇒ dikalikan silang
×-1 7
7(y-3)=-8(×-1)
7y-21=-8×+8
7y= -8×+8+21
7y= -8×+29