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1²=(x-0)²+(y-0)²
x²+y²=1
(x - 0)² + (y - 0)² = r²
x² + y² = r²
melalui (0,1) ⇒ 0² + 1² = r²
1 = r²
maka persamaan lingkarannya:
x² + y² = 1