Question

Tuliskan 5 suku pertama barisan geometri apabila dik U3 = 8 dan U9 = 512

Answer 1

U3...ar^2 = 8
u9..ar^8 = 512

r^6 = ar^8/ar^2= 512/8 =64
r = 2

ar^2 = 8
a * 2^2 = 8
a * 4 = 8
a = 8/4=2

u1..a = 2
u2..ar = 2*2 = 4
u3  ar^2 = 2*4 = 8
u4= 8*2 = 16
u5=16*2=32
2,4,8,16,32