Tres numeros impares consecutivos suman 159.¿cual es el mayor numero?
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X+3=B
X+5=A
A+B+C=159
(X+1)+(X+3)+(X+5)=159
ENTONCES SE SUMAN TODAS LAS X Y TODOS LOS NUMEROS Y QUEDA ASI X+X+X+1+3+5=159
3X+9=159
3X=159-9
3X=150
X=150/3
X=50
NUMERO MAYOR
X+5=A
A=X+5
A=50+5
A=55