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3n + 3 = 60
3n = 57
n = 19
19, 20 y 21
t + t + 1 + t + 2 = 60
t + t + t + 1 + 2 = 60
3t + 3 = 60
3t = 60 - 3
3t = 57
t = 57/3
t = 19
t + 1 = 19 + 1 = 20
t + 2 = 19 + 2 = 21
Solución : Los números son : 19, 20 y 21