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Planteamos la ecuación.
x + (x + 1) + (x + 2) = 204
x + x + 1 + x + 2 = 204
3x + 3 = 204
3x = 204 - 3
3x = 201
x = 201/3
x = 67
Ahora lo sumamos lo sumamos consecutivos.
x + 1 = 67 + 1 = 68
x + 2 = 67 + 2 = 69
Los números son: 67, 69 y 69.
Sean los números consecutivos x, x+1 y x+2, entonces
x + x+1 + x+2 = 204
3x + 3 = 204
3x = 204 - 3
3x = 201
x = 201/3
x = 67
R/ Los 3 números son 67, 68 y 69.
Efectivamente 67 + 68 + 69 = 204