V = 720m/6min
V = 720m/360s
V = 2m/s
V = (2*3,6)km/h
V = 7,2km/h
t = S/V
t = 10,8km:7,2km/h
t = 1,5h
720m - 0,72km
z proporcji
0,72km - 6min
10,8km - x
0,72x=6*10,8
0,72x=64,8 |:0,78
x=90
90min=1,5h
Traktor przejedzie 10,8km w 1,5h
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V = 720m/6min
V = 720m/360s
V = 2m/s
V = (2*3,6)km/h
V = 7,2km/h
t = S/V
t = 10,8km:7,2km/h
t = 1,5h
720m - 0,72km
z proporcji
0,72km - 6min
10,8km - x
0,72x=6*10,8
0,72x=64,8 |:0,78
x=90
90min=1,5h
Traktor przejedzie 10,8km w 1,5h
S= 720m
V= S:t
V= 720m: 360s = 2m/s
t=?
V=2m/s
S=10,8km=10800m
t= 10800m;2m/s= 5400s
5400s: 60=90min
Odp: ten traktor pokona drogę równą 10,8 km po upłuwie 90 minut.