jawab
1 x 3 = 1 (2 + 1 )= 1 (2.1 + 1)
2x 5 = 2(4 + 1) = 2 (2.2 + 1)
3 x 7 = 3 (6 + 1) = 3 (2.3 + 1)
4 x 9 = 4 (8+ 1) = 4 (2.4) + 1
..
untuk suku ke n = n (2n +1)
penulisan notasi sigma nya adalah
4
∑ k (2k + 1)
k = 1
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Verified answer
jawab
1 x 3 = 1 (2 + 1 )= 1 (2.1 + 1)
2x 5 = 2(4 + 1) = 2 (2.2 + 1)
3 x 7 = 3 (6 + 1) = 3 (2.3 + 1)
4 x 9 = 4 (8+ 1) = 4 (2.4) + 1
..
untuk suku ke n = n (2n +1)
penulisan notasi sigma nya adalah
4
∑ k (2k + 1)
k = 1