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x² - 9 = 4² = 16
x² = 25
x = 5 atau x = -5
x >0 , x # 1 --> x = 5
x'log 125 = 5'log 5^3 = 3
..
9^(3'log(x-1)) = 25
3^(3'log(x-1)^2) = 25
(x-1) ^2 = 25 dengan x - 1 > 0 --> x > 1
(x-1) = 5 atau x-1 = -5
x = 6 atau x = - 4 (TM) krn x tidak memenuhi x > 1
x = 6