Penjelasan dengan langkah-langkah:
diketahui sudut ACD = 2x°
sudut DCB = 3x + 30°
diketahui ACD + DCB = 180°
maka = 2x + 3x + 30 = 180°
= 5x = 180° - 30
= 5x = 150°
= x = 150° ÷ 5
= x = 30°
didapat x = 30°
jadi, sudut ACD = 2x° = 2 (30°) = 60°
sudut DCB = 3x + 30° = 3 (30°) + 30° = 90° + 30° = 120°
Jawaban:
60°
pertama tama kita cari nilai x dulu.
karena sudut ACD dan sudut DCB berpelurus maka jika dijumlah sudutnya 180°
<ACD + <DCB = 180°
2x + (3x + 30°) = 180°
2x + 3x + 30° = 180°
5x + 30° = 180°
5x = 150°
x = 150°/5
x = 30°
<ACD = 2x
= 2 x 30°
= 60°
<DCB = 3x + 30°
= 3(30°) + 30 °
= 90° + 30°
= 120°
mohon dicek lagi ya semoga membantu...
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Penjelasan dengan langkah-langkah:
diketahui sudut ACD = 2x°
sudut DCB = 3x + 30°
diketahui ACD + DCB = 180°
maka = 2x + 3x + 30 = 180°
= 5x = 180° - 30
= 5x = 150°
= x = 150° ÷ 5
= x = 30°
didapat x = 30°
jadi, sudut ACD = 2x° = 2 (30°) = 60°
sudut DCB = 3x + 30° = 3 (30°) + 30° = 90° + 30° = 120°
Jawaban:
60°
Penjelasan dengan langkah-langkah:
pertama tama kita cari nilai x dulu.
karena sudut ACD dan sudut DCB berpelurus maka jika dijumlah sudutnya 180°
<ACD + <DCB = 180°
2x + (3x + 30°) = 180°
2x + 3x + 30° = 180°
5x + 30° = 180°
5x = 150°
x = 150°/5
x = 30°
<ACD = 2x
= 2 x 30°
= 60°
<DCB = 3x + 30°
= 3(30°) + 30 °
= 90° + 30°
= 120°
mohon dicek lagi ya semoga membantu...