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12000 = 2500 × 0,2 × (30-x)
x-30 = 12000 / 2500 × 0,2
×-30 = 24
x = 24 + 30 = 54°C
2. Qa = mcT = 250 × 0,5 × (0-(-5) = 250 × 0,5 × 5 = 625 kal
Qb = mcT = 250 × 80 = 20000 kal
total kalor = 20000 + 625 = 20625 J