Question

tolongg bantuin dong, pakai cara, soalnya besuk di kumpulkan



#bilangan berpangkat pecahan dan operasinya

​

Answer 1

Penjelasan dengan langkah-langkah:

[tex]a. \: \sqrt{289} = \sqrt{ {17}^{2} } = {17}^{ \frac{2}{2} } = {17}^{1} = 17[/tex]

[tex]b. \: - \sqrt{676} = - \sqrt{67 {}^{2} } = - 26[/tex]

[tex]c. \: 2 \sqrt[3]{343} = 14[/tex]

[tex]d. \: \sqrt{ \sqrt{256} } = \sqrt{16} = 4[/tex]

[tex] e. \: \sqrt[3]{ \sqrt{729} } = 9[/tex]

[tex]f. \: \sqrt{324} + \sqrt[3]{1.331} = 18 + 4 = 29[/tex]

[tex]a. \: \sqrt{ {29}^{2} - {20}^{2} } = \sqrt{85264 - 400} = \sqrt{84864} = 8 \sqrt{1326} [/tex]

[tex]b. \: \sqrt{ {2}^{6} + {3}^{4} + {12}^{2} } = \sqrt{64 + 81 + 144} = \sqrt{289} = 17[/tex]

Semoga membantu ;)