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massa BaSO4 = 1,165 gr , Mr BaSO4 = 233
mol BaSO4 = 1,165 gr / 233 gr/mol = 0,005 mol
mol BaCl2 = mol BaSO4 (koefisien sama) = 0,005 mol
Mr BaCl2 = 208
massa BaCl2 = 0,005 mol x 208 gr/mol = 1,04 gr
massa H2O = 1,22 gr - 1,04 gr = 0,18 gr
mol H2O = 0,18 gr / 18 gr/mol = 0,01 mol
xH2O = 0,01 / 0,005 = 2
jumlah air kristal BaCl2 = 2
BaCl2.2H2O