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⁷log (x²+2x-8) = 1
x²+2x -8 = 7
x²+2x-15=0
(x+5) (x-3) = 0
x= -5 atau x = 3
x<-5 atau x>3
7log(x^2+2x-8)>7log(7)
x^2+2x-8>7
x^2+2x-15>0
(x+5)(x-3)>0
x<-5 atau x>3
;)