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C2H4+3O2 --> 2CO2+2H2O delta Hc=-1410 KJ/mol
2. delta H (13 gram) = mol C2H6/1 * delta H
mol C2H6=gram/MR=13/30
delta H = 13/30*226,7
delta H=98,236 KJ
delta H=98.236 J
3. dit delta H d =?
delta Hf=-365,6 KJ/mol
delta Hd=+365,6 KJ/mol
mol=1/80
delta H (1 gram) =mol/1*delta Hd
delta H =1/80*365,6 KJ/mol
delta H=4,57 KJ/mol