Naja2512
A. sudut AEF = sudut BCA BC = AE (sebanding) AC = EF (sebanding) B. skala = 1:2 EF = 1/2 AC = 1/2 8 = 4 cm AF = 1/2 AB = 1/2 10 = 5 cm CF = AC - AF = 8 - 5 = 3 cm
Maaf jika salah
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drusyadnurdin
A. Jika sudut BAC = x (=sudut EAF), maka sudut AFE = 180-x-o, demikian pula untuk sudut ABC = 180-x-o. Sudut2 yang bersesuaian dr masing-masing segitiga adalah sama besar, maka bisa dipastikan bila kedua segitiga tersebut sebangun. b. panjang EF => EF/AE = BC/AC => EF = BC/AC * AE = 12/8 * 6 = 3 cm panjang CF: => AC = AF + CF, dimana AC = 12, maka: CF = 12 - AF => AF/AE = AB/AC => AF = AB/AC * AE => AF = (6+4)/12 * 6 => AF = 5 cm Maka: CF = 12 - 5 = 7 cm
BC = AE (sebanding)
AC = EF (sebanding)
B. skala = 1:2
EF = 1/2 AC
= 1/2 8
= 4 cm
AF = 1/2 AB
= 1/2 10
= 5 cm
CF = AC - AF
= 8 - 5
= 3 cm
Maaf jika salah
b. panjang EF
=> EF/AE = BC/AC
=> EF = BC/AC * AE = 12/8 * 6 = 3 cm
panjang CF:
=> AC = AF + CF, dimana AC = 12, maka: CF = 12 - AF
=> AF/AE = AB/AC
=> AF = AB/AC * AE
=> AF = (6+4)/12 * 6
=> AF = 5 cm
Maka: CF = 12 - 5 = 7 cm