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->aloga⁴- a⁴loga
= 4.aloga-¼aloga
= 4.1-¼.1
= 4 - ¼
= 16/4 - ¼
= 15/4
= 3¾
8. [alog(bc)⁴]^(½)
=[4(alogb+alogc)]^(½)
[4(4+alogb.blogc)]^(½)
[4(4+alogb.1/clogb)]^(½)
[4(4+4.1/4)]^(½)
[4(5)]^(½)
20^(½)=√20=2√5
9. log 1=0
-> 10^(0) = 1 (terbukti)
log10=1
-> 10¹=10 (terbukti)
10. maaf, saya kurang paham bukannya a>b>0 dengan 0<b<a sama saja?
maaf udh mentok