Question

tolong yaa !!!

persamaan garis lurus yg melalui titik A(3,-4) dan B(6,8) adalah ???

Answer 1

A(3,-4)  B(6,8)
x1=3
x2= 6
y1= -4
y2=8
y-y1/y2-y1 =x-x1/x2-x1
y-(-4) / 8-(-4) = x-3 / 6-3
y+4 / 8+4 = x-3 / 6-3
y+4/12 = x-3/3
3(y+4) = 12(x-3)
3y+12 = 12x-36
12x-3y = 12+36
12x-3y = 48 (disederhanakan dgn sama2 dibagi 3)
4x-y = 16