Tolong yaa , perlu nya sekarang.... Question from @syeha

Takamori37 Nomor 1.
$\sqrt[7]{a^5}\times\sqrt[7]{a^3} \\ a^{5/7}\times a^{3/7} \\ a^{8/7} \\ a\times a^{1/7} \\ a\sqrt[7]{a}$

Nomor 2.
Bag a.
$(4+\sqrt{3})^2 \\ =4^2+2.4.\sqrt{3}+\sqrt{3^2} \\=16+8\sqrt{3}+3 \\ =19+8\sqrt{3}$

Bag b.
$(2\sqrt{2}-\sqrt{5})^2\\=(2\sqrt{2})^2-2.2\sqrt{2}.\sqrt{5}+\sqrt{5^2} \\ =8-4\sqrt{10}+5 \\ =13-4\sqrt{10}$

Nomor 3.
$$\begin{align}\frac{3}{\sqrt{7}}&=\frac{3}{\sqrt{7}}\times\frac{\sqrt{7}}{\sqrt{7}} \\ &=\frac{3}{7}\sqrt{7}\end{align}$

$$\begin{align}\frac{2-\sqrt{5}}{2+\sqrt{5}}&=\frac{2-\sqrt{5}}{2+\sqrt{5}}\times\frac{2-\sqrt{5}}{2-\sqrt{5}} \\ &=\frac{4-4\sqrt{10}+5}{2^2-5} \\ &=\frac{9-4\sqrt{10}}{-1} \\ &=4\sqrt{10}-9\end{align}$

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syeha yang lain ada?

syeha yang nomer 3 bisa bantu ? soalnya yang nomor 2 uda siap

Takamori37 Sudah semuanya dijawab.

dumatheresia 1. $\sqrt[7]{a ^{5} }. \sqrt[7]{ a^{3} } = a^{ \frac{5}{7} } . a^{ \frac{3}{7} } = a^{ \frac{8}{7} } \\ a . \sqrt[7]{a}$
2. a) (4 + √3)² = 16 + 8√3 + 3 = 19 + 8√3
b) (2√2 - √5)² = 4.2 - 4√10 + 5 = 8 + 5 - 4√10 = 13 - 4√10
3. a) 3/√7 × √7/√7 = 3√7 / 7 atau 3/7. √7
b) $\frac{2- \sqrt{} 5}{2 +\sqrt{5} } . \frac{2- \sqrt{} 5}{2- \sqrt{5} } = \frac{4-4 \sqrt{5}+5 }{4-5} \\ \frac{9-4 \sqrt{5} }{-1} =-9+4 \sqrt{5}$

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Sekarang di perlukan Sama jalan yaa. Thanks

Tolong banget yaaa, sekalian jalan nya jugak✌️

1-5 please, please banget

Please 1 -5 sama jalannya please

Tolong bantu dong dari 1- 5 aja please

Yang tau cara stand up comedy lucu kaliii , tolong bantu yaa

Yang tau tentang topologi bus

Yang tau topologi bus, tolong kerja sama nya ya

Siapa paham Form Php dan CRUD (Create Read Update Delete) please bantuin Poinnya lumayan loo

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