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5) a^(5/3 - 7/6) × b^(1/2 - 1/2) - a^(2/3-2/3) × b^(3/2 - 1)
a^3/6 - b^1/2
a^1/2 - b^1/2
7) [2^((n + 2) × 2) - 2² × 2^(2n)]/2^n × 2^(n + 2)
= 2^(2n+4) - 4 × 2^(2n - n - n - 2)
= 2^(2n + 4) - 4 × 2^(-2)
= 2^(2n + 4) - 4 × 1/4
= 2^(2n + 4) - 1