Question

tolong ya pakai cara ...jangan ngasal​

Answer 1

Penjelasan dengan langkah-langkah:

6). (3a)⁴ = 3a x 3a x 3a x 3a (D)

7). b¹² : b³ = b¹²-³ = b⁹ (D)

8). (4 x 3^-6)(5 x 3⁴) = (4x5)(3^(-6+4)= 20 x 3^-2 (D)

9). (-4)^-4 x (2 x 4⁵) : 32 = 1/(-4)⁴ x (2 x (2²)⁵) : 2⁵ = 1/256x (2 x 2¹⁰) : 2⁵ = 1/2⁸ x 2¹¹ : 2⁵ = 2¹¹-⁸-⁵ = 2^-2 = 1/2² = 1/4 = 4^-1 (C)

10). (-5)³ x (-2)³ x 3³ = (-5).(-5).(-5) x (-2).(-2).(-2) x (3.3.3) = (-125) x (-8) x 27 = 1.000 x 27 = 27.000 = 30³ (B)

11). (p⁶ x p^-2)/(p^-3 x p⁵) = p^(6-2)/ p^(-3+5)= p⁴/p² = p⁴-² = p² (C)

Answer 2

Penjelasan dengan langkah-langkah:

(3a)⁴ = 3a x 3a x 3a x 3a (D)

b¹² : b³ = b¹²-³ = b⁹ (D)

(4 x 3^-6)(5 x 3⁴) = (4x5)(3^(-6+4)= 20 x 3^-2 (D)

(-4)^-4 x (2 x 4⁵) : 32 = 1/(-4)⁴ x (2 x (2²)⁵) : 2⁵ = 1/256x (2 x 2¹⁰) : 2⁵ = 1/2⁸ x 2¹¹ : 2⁵ = 2¹¹-⁸-⁵ = 2^-2 = 1/2² = 1/4 = 4^-1 (C)

(-5)³ x (-2)³ x 3³ = (-5).(-5).(-5) x (-2).(-2).(-2) x (3.3.3) = (-125) x (-8) x 27 = 1.000 x 27 = 27.000 = 30³ (B)

(p⁶ x p^-2)/(p^-3 x p⁵) = p^(6-2)/ p^(-3+5)= p⁴/p² = p⁴-² = p² (C)