Tolong ya no 9 & 10, makasih.... Question from @refo13

October 2018 1 33 Report

Tolong ya no 9 & 10, makasih

hendrisyafa 9) a. $PR= \frac{2}{3}PQ$

$= \frac{2}{3}(q-p)$

$= \frac{2}{3}( \left[\begin{array}{ccc}-1\\2\\\end{array}\right] -\left[\begin{array}{ccc}5\\7\\\end{array}\right] )$

$= \frac{2}{3}( \left[\begin{array}{ccc}-6\\-5\\\end{array}\right])$

$= \left[\begin{array}{ccc}-4\\- \frac{10}{3} \\\end{array}\right]$

PQ = q-p
$=\left[\begin{array}{ccc}-1\\2 \\\end{array}\right]-\left[\begin{array}{ccc}5\\-7 \\\end{array}\right]$

$=\left[\begin{array}{ccc}-6\\9 \\\end{array}\right]$

$PR.PQ=\left[\begin{array}{ccc}-4\\- \frac{10}{3} \\\end{array}\right].\left[\begin{array}{ccc}-6\\9 \\\end{array}\right]$

$PR.PQ=(-4 )(-6)+(-\frac{10}{3})(9)$

$PR.PQ=24-30$

$PR.PQ=-6$

b) PR = r - p

$\left[\begin{array}{ccc}-4\\- \frac{10}{3} \\\end{array}\right]=r- \left[\begin{array}{ccc}-1\\2\\\end{array}\right]$

$r= \left[\begin{array}{ccc}-4\\- \frac{10}{3} \\\end{array}\right]+ \left[\begin{array}{ccc}-1\\2\\\end{array}\right]$

$r= \left[\begin{array}{ccc}-5\\- \frac{4}{3} \\\end{array}\right]$

QR = r - q
= $\left[\begin{array}{ccc}-5\\- \frac{4}{3} \\\end{array}\right]- \left[\begin{array}{ccc}-1\\2 \\\end{array}\right]$

= $\left[\begin{array}{ccc}-6\\- \frac{10}{3} \\\end{array}\right]$

$QR.PQ=\left[\begin{array}{ccc}-6\\- \frac{10}{3} \\\end{array}\right].\left[\begin{array}{ccc}-6\\9 \\\end{array}\right]
$

$QR.PQ=(-6)(-6)+(- \frac{10}{3})(9)$

$QR.PQ=36- 30$

$QR.PQ=6$

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