Nomor 13
f(x) = (4x - 8) / (2x + 10)
f`¹(x) = (-10x - 8) / (2x - 4)
= -(10x + 8) / -(4 - 2x)
= (10x + 8) / (4 - 2x)
jawaban B
Nomor 14
Karna bentuk tidak 0/0 maka nilai langsung dimasukkan
lim x->3 (x² + 2x - 1) / (x² - 9)
= (3² + 2(3) - 1) / (3² - 9)
= (9 + 6 - 1) / 0
= 14/0
= ~
Jawaban A
Mapel : Matematika
Bab : Limit fungsi aljabar
Kode : 11.2.8
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Nomor 13
f(x) = (4x - 8) / (2x + 10)
f`¹(x) = (-10x - 8) / (2x - 4)
= -(10x + 8) / -(4 - 2x)
= (10x + 8) / (4 - 2x)
jawaban B
Nomor 14
Karna bentuk tidak 0/0 maka nilai langsung dimasukkan
lim x->3 (x² + 2x - 1) / (x² - 9)
= (3² + 2(3) - 1) / (3² - 9)
= (9 + 6 - 1) / 0
= 14/0
= ~
Jawaban A
Mapel : Matematika
Bab : Limit fungsi aljabar
Kode : 11.2.8