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b+1, b-1, b-5
b-1/b+1 = b-5/b-1
⇔(b-1).(b-1) = (b-5).(b+1)
⇔b²-2b+1 = b² + b - 5b - 5
⇔b² - 2b + 1 = b² - 4b - 5
⇔b² - b² - 2b + 4b + 1 + 5 = 0
⇔2b + 6 = 0
⇔2b = -6
⇔b = -3