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Suhu
Pendahuluan
1. 24°C = 19,2 °R
2. 36°R = 113 °F
3. 283 K = 10 °C
Pembahasan
Ingat
R = 4/5 × C
F = 9/4 x R + 32
C = K - 273
1) 24 °C = 19,2 °R
R = 4/5 × C
R = 4/5 × 24
R = 4× 24 / 5
R = 96 / 5
R = 19, 2
2) 36°R = 113 °F
F = 9/4 x R + 32
F = 9/4 × 36 + 32
F = 9 × 9 + 32
F = 81 + 32
F = 113
3) 283 K = 10 °C
C = K - 273
C = 283 - 273
C = 10
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Pelajari Lebih Lanjut
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Detail Jawaban
Mapel : Fisika
Kelas : 7
Bab : Suhu
Kode soal : 2
Kata kunci : Suhu (Celcius, Kelvin )
Kode kategorasi : 7.2.5
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