Question

tolong ya kaaka
hitung perbandingan luas ABCD dengan APQR​

Answer 1

kesebangunan

jajar genjang ABCD sebangun jajar genjang APQR

BC/DC = PQ/RQ = t1/t2 = 20/25 = 4/5

Keliling APQR = 36 cm

2(4x + 5x) = 36

2 × 9x = 36

x = 36/18

x = 2

RQ = 5x = 10 cm

PQ = 4x = 8 cm

perbandingan luas ABCD dan APQR

= (a1 × t1) : (a2 × t2)

= (a1/a2) × (t1/t2)

= (DC/RQ) × 4/5

= 25/10 × 4/5

= 100/50

= 2 : 1