" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a = baris (3 1) dikali kolom (1 2) = 3(1) + 1(2) = 5
b ada di baris 2 kolom 1
b = baris (-1 3) dikali kolom (-3 0) = (-1)(-3) + 3(0) = 3
c ada di baris 3 kolom 1
c = baris (-2 -2) dikali kolom (-3 0) = (-2)(-3) + (-2)(0) = 6
√(2a + 3b + c) = √(2 . 5 + 3 . 3 + 6) = √(10 + 9 + 6) = √25 = 5