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1.r=20cm=0,2m
I = 1/2mr^2
l=1/2.5.(0,2)^2
l=1/2.5.2/5
l=1
∑T = I.α
Fr = I.α
6.0,2=1.a
a=1,2/1
a=1,2
Jawaban:B
2.(2,8)=(6,2) metode gauss
6:2
2
2
jadi titik beratnya 3:2:2
Jawaban B
Semoga membantu :)
jadikan jawaban terbaik yah !!