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2 log (x(x-6)) = 4
2log x^2 - 6x = 4
x^2 - 6x -16 = 0
(x+2) (x-8)
x1 = -2 ---->>> '2 log x" -ada tanda negatif di log itu tidak diketahui nilainya-
x2 = 8 ----->>> 2log 8 + 2log (8-6) = 3 + 2log2= 3 + 1 = 4
HP={8}
yang b ga tau
2log-6x=2log16
-6x-16=0
(x+2)(x-8)
x=-2 atau x=8