Question

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Answer 1

∠OAB + ∠BAC = 180
2x + 3x - 30 = 180
5x = 180 + 30
5x = 210
x = 210/5
x = 42

a) ∠OAB = 2x = 2(42) = 84°

b) ∠BAC = 3x - 30
= 3(42) - 30
= 126 - 30
= 96°

c) ∠BCO = 1/2 × (180 - ∠BAC)
= 1/2 × (180 - 96)
= 1/2 × 84
= 42°

d) ∠CBO = 1/2 × (180 - ∠OAB)
= 1/2 × (180 - 84)
= 1/2 × 96
= 48°