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Anode : Fe(s) ---> Fe₂ (aq) + 2e⁻ E = + 0,44 V
Katode : O₂(g) + 2 H₂O + 4e⁻ ---> 4OH⁻ E = + 0,40 V
Selanjutnya akan terbentuk senyawa oksida terhidrasi yaitu : Fe₂O₃ x H₂O