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Fc = k.(q1 × q2)/r²
k = 9 × 10^9 N.m²/C² (Konstanta Gaya Coulomb)
q = Muatan Benda (C)
r = jari-jari (m)
Fc = 9 × 10^9 × (6,67 × 10^-10 × 5,34 × 10^-9)/(0,08)²
Fc = {9 × 6,67 × 5,34 ÷ 64} × 10^-6
Fc = 4,99 × 10^-6
Fc = 5 × 10^-6
Fc = 0,5 × 10^-5 N
Fc = 0,5 Dyne
Fc = ½ Dyne
Jawabannya adalah C.
→ 1 StatCoulomb = 3,3 × 10^-10 Coulomb
→ Dyne = 1 × 10^-5 N
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