Question

tolong step by step! ​

Answer 1

Misal, [tex] x-1 = a \Leftrightarrow x = a+1, [/tex] maka berlaku:

[tex] \begin{aligned} f(x-1) &= x^2-2x+1 \\ f(a) &= (a+1)^2-2(a+1)+1 \\ f(a) &= a^2+2a+1-2a-2+1 \\ f(a) &= a^2 \end{aligned} [/tex]

Ubah [tex] a \rightarrow x, [/tex] sehingga:

[tex] f(x) = x^2[/tex]

Jadi, jawaban yang tepat adalah C.