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Sifat Nilai mutlak : |f(x)| < |g(x)| ⇔ (f(x))² < (g(x))²
|3 - x| < 4
⇒ (3 - x)² < 4²
⇒ x² - 6x + 9 < 16
⇒ x² - 6x - 7 < 0
⇒ (x + 1)(x - 7) < 0
Zero Maker x = -1, x = 7
Jadi, batas-batasnya
-1 < x < 7
Jawba : D
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