Question

Tolong soal mat no 22 pake cara please...

Answer 1

(tan α + cot α)/cosec α
= (tan α + 1/tan α)/cosec α
= ((tan^2 α + 1)/tan α)/cosec α
= sec^2 α/(tan α . cosec α)
= sec^2 α/(sin α/cos α . 1/sin α)
= sec^2 α/(1/cos α)
= sec^2 α . cos α
= 1/cos^2 α . cos α
= 1/cos α
= sec α

Jawaban: A