Question

tolong selesaiin tugas aljabar​

Answer 1

Jawaban:

2x (3x+4y) = 6x² + 8xy.

3y (2x+6y) = 6xy + 18y².

4y (2x+3y) = 8xy + 12y².

x (x²-x+1) = x³-x²+x.

4x (x²+2+8) = 4x³+8x+32x

2(3x+4) + 6x(x+2) = 6x+8+6x²+12x = 6x²+18x+8.

‐4 (x+6) - 2(4x-6) = -4x-24-8x+12=-12x-12.

6x(2x-3y) = 12x²-18xy.

6(x²+2+1) = 6x²+12+6.

2(6x+3y-4) = 12x+6y-8.