DERET ARITMETIKA
Jumlah n suku pertama (Sn) :
Sn = 4n² - n
Suku ke-11
= U11
= S11 - S10
= (4.11² - 11) - (4.10² - 10)
= 4(11² - 10²) - 11 + 10
= 4(121 - 100) - 1
= 4 × 21 - 1
= 84 - 1
= 83
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DERET ARITMETIKA
Jumlah n suku pertama (Sn) :
Sn = 4n² - n
Suku ke-11
= U11
= S11 - S10
= (4.11² - 11) - (4.10² - 10)
= 4(11² - 10²) - 11 + 10
= 4(121 - 100) - 1
= 4 × 21 - 1
= 84 - 1
= 83