Question

Tolong,,, PR MTK bilangan berpangkat
no. 2 C

Answer 1

[4a^(3-5) b^(8-1)] [(16 b^³*² a^¹*²) / (8a^³*²)]
= [4a^-² b^7] [2b^6 a^²-6]
= 8 a^(-2 + (-4)) b^(7+6)
= 8a^-6 b^13
=(8b^13) / a^6