Question

Tolong pale cara kerjanya, skarang...

Answer 1

1) (x,y) + T(-3, 2) = (x' , y' )
x= x' + 3
y= y' - 2
.
y= x² + 1 --> (y' - 2) = (x' +3)²  + 1
y - 2 = x² + 6x + 9 + 1
y = x² + 6x +9 + 1 + 2
y = x² +6x  + 12

2) (a', b') = (3,- 2) + (a, b)
a'= 3+ a --> a = a' - 3
b' = b - 2 --> b = b' + 2

bayangannya x² + y² + 6x - 2y  + 9 = 0
(x +3)² + (y -1)² = -9+9+1 =1
,
persamaan awal
(x-a)² + (y-b)² - 1 = 0
banyangannya 
(x - (a' -3))² + (y-(b' +2))² - 1= (x+3)² + (y-1)² -1 = 0
-(a-3) = 3 --> -a + 3 = 3
-a = 0
a = 0

- (b+2) = - 1
-b - 2 =- 1
-b = -1+ 2 
-b = 1
b = -1

a.b = 0

Answer 2

Jawaban no.6 adalah c. (-3,3)