Question

Tolong pake cara yahhh








ありがとうございます～～

Answer 1

Laju kalor di P = Laju kalor di Q

kp.Ap.(60-tB)/Lp = kq.Aq.(tB- 30)

kp.(60-tB) = kq.(tB- 30)

2.kq.(60-tB)= kq.(tB- 30)

2.(60-tB)= tB- 30

120 - 2.tB = tB - 30

3.tB = 150

tB = 150/3 = 50 °C

Jawaban. D

Gambatte kudasaine.