Question

Tolong pake cara, jgn ngasal​

Answer 1

Verified answer

Jawaban:

a. panjang DE

[tex]de = \sqrt{ {16}^{2} + {12}^{2} } \\ de = \sqrt{256 + 144} \\ de = \sqrt{400} \\ de = 20[/tex]

b. panjang PG

[tex]pg = \sqrt{ {15}^{2} - {12}^{2} } \\ pg = \sqrt{225 - 144} \\ pg = \sqrt{81} \\ pg = 9[/tex]

c. keliling DEFG

DEFG = 20+20+15+15

DEFG=70 cm

[tex]d.luas \: abcd \\ luas = \frac{1}{2} \times d1 \times d2 \\ luas = \frac{1}{2} \times 24 \times 25 \\ luas = 300 {cm}^{2} [/tex]

jadikan yg terbaik ya he he