Jawaban:
panjang AD
[tex]ad = \sqrt{ {15}^{2} + {8}^{2} } \\ ad = \sqrt{225 + 64} \\ ad = \sqrt{289} \\ ad = 17cm[/tex]
keliling ABCD
K= 17+17+10+10
K=54 cm
[tex]luas \: abcd = \frac{1}{2} \times d1 \times d2 \\ luas \: abcd = \frac{1}{2} \times 21 \times 16 \\ luas \: abcd = 168 {cm}^{2} [/tex]
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Verified answer
Jawaban:
panjang AD
[tex]ad = \sqrt{ {15}^{2} + {8}^{2} } \\ ad = \sqrt{225 + 64} \\ ad = \sqrt{289} \\ ad = 17cm[/tex]
keliling ABCD
K= 17+17+10+10
K=54 cm
[tex]luas \: abcd = \frac{1}{2} \times d1 \times d2 \\ luas \: abcd = \frac{1}{2} \times 21 \times 16 \\ luas \: abcd = 168 {cm}^{2} [/tex]