Diketahui:
sudut = 120°
A = 4 km
B = 3 km
Ditanyakan:
jarak A dan B
Jawab:
jarak = √(A²+B²-2ABcos120°)
= √(4²+3²-2(4)(3)(-1/2))
= √(16+9+12)
= √37 (C)
Mapel: Matematika
Kelas: 10
Materi: Trigonometri
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Diketahui:
sudut = 120°
A = 4 km
B = 3 km
Ditanyakan:
jarak A dan B
Jawab:
jarak = √(A²+B²-2ABcos120°)
= √(4²+3²-2(4)(3)(-1/2))
= √(16+9+12)
= √37 (C)
Mapel: Matematika
Kelas: 10
Materi: Trigonometri